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Dear All, I am posting a problem after a long time. Try this out and post your answer in the comment section. QUESTION: A mother has four children, each with a di erent age. The product of their ages is 17 280. The sum of the ages of the three oldest children is 40 and the sum of the ages of the three youngest children is 32. Determine the ages of the four children. All the best!

Dear All Try this one also : well, 2 students have solved this correctly. well done!!! Here is the solution:

Dear All Solve the following question: Here is the Solution:

Dear All Solve the following question: well, we have a quick respose by Prabhat. Well done! I will appriciate if you could give your responses in the comment section of the post. Anyways, here is the solution:

Dear All Today, I am posting a very interesting problem. Waiting for your responses... QUESTION: Two women Mrs. X and Mrs. Y met each other in a park. Mrs. X : ‘‘Hi, how are you? How are your children? You have three children if I remember correctly. But how old are they now?’’ Mrs. Y : ‘‘Yes, I have three children. The product of their ages is equal to 36. The sum of their ages is equal to number of chairs lying in a park.’’ Mrs. X counted the number of chairs, thought for a while and said, ‘‘ I still can’t figure out the ages of your children.’’ Mrs. Y : ‘‘ My eldest son will definitely won math olympiad this year.’’ What are the ages of the three children? (Assume whole number for ages) Well, Here is the answer:

Dear All A simple question for you all:

Dear All Writing after so long... I was busy doing many other assignments. So, here is a question for you :) Question : Twenty matchsticks of equal length are placed to form a triangle. Find the total number of different triangles that can be made with a perimeter of 20 matchsticks? ANSWER:

Dear All Due to some unavoidable circumstances, i was not able to blog for many days. Really missed it! Anyways, I have a problem for you .Try it... Sumit went to the shopping centre to buy supplies for his mathematics project. He spent half of what he had plus Rs. 2 in the firts shop, half of what he then had left plus Rs. 1 in the second shop; half of what he then had left plus Re. 1 in the third shop and, in the fourth shop half of all he had left. Three Rs. were left over. How much money did he start with? ANSWER: Have fun and enjoy mathematics.

Dear All Some Native Americans had a very interesting way of doing this. To see how high a tree was, they would find a spot where, looking under their legs (as shown), they could just see the top of the tree. The distance from such a spot to the base of the tree was approximately the height of the tree. Why does this work? The reason is quite simple. For a normal, healthy adult, the angle formed by looking under one's legs is approximately 45 o . Hence, the distance to the tree must be around the same as the height of the tree.

I met a youngster rummaging through a dust bin. He seemed to be interested only in large sheets of paper. "What are you doing?" "I am trying to get to the moon." "Are you going to make a paper spaceship?" "No, it's much simpler than that." He put one piece of newspaper down and stood on it. "I am now nearer to the moon." He doubled the paper and stood on that. Then doubled again and stood on top of that -- there were now 4 thicknesses of paper, say a total of 4/10 of a millimetre and he carried on doubling. After a few more doublings I began to get the idea. It is roughly 400000km to the moon. How many times must he double? Surprisingly, the answer is only 43. The pattern is 1, 2, 4, 8, 16,..., each term doubling the previous one. Such a sequence is called a Geometric Progression and the nth term is given by 2^(n-1). Geometric Progressions (GP's) often have terms which get very big like this one. For some GP's however, the t...

Hello All A positive integer N is a Palindrome if the number obtained by reversing the sequence of the digits of N is equal to N. The year 1991 was the only year of the last century which was a palindromic year. Read this document to solve this interesting problem. Write your answers in the comment section.

Draw a triangle, any triangle (although it may be best to start with an acute triangle). 1) Mark the midpoints of each side (3 points). See Figure 1. 2) Drop an altitude from each vertex to the opposite side, and mark the points where the altitudes intersect the opposite side. (If the triangle is obtuse, an altitude will be outside the triangle, so extend the opposite side until it intersects.) See Figure 2. 3) Notice that the altitudes intersect at a common point. Mark the midpoint between each vertex and this common point. See Figure 3. No matter what triangle you start with, these nine points all lie on a perfect circle! Even simple geometry still has some surprises in store! This result was known by Euler in 1765, but rediscovered by Feuerbach in 1822.

Take any triangle, and construct equilateral triangles on each side whose side lengths are the same as the length of each side of the original triangle. Surprise: the centers of the equilateral triangles form an equilateral triangle! This theorem is credited to Napoleon, who was fond of mathematics, though many doubt that he knew enough math to discover it!

Here's a famous unsolved problem: is every even number greater than 2 the sum of 2 primes? The Goldbach conjecture , dating from 1742, says that the answer is yes. Some simple examples: 4=2+2, 6=3+3, 8=3+5, 10=3+7, ..., 100=53+47, ... What is known so far: Schnirelmann(1930): There is some N such that every number from some point onwards can be written as the sum of at most N primes. Vinogradov(1937): Every odd number from some point onwards can be written as the sum of 3 primes. Chen(1966): Every sufficiently large even integer is the sum of a prime and an "almost prime" (a number with at most 2 prime factors). Try it! Its really very interesting. Well! Can you prove or disprove Goldbach’s conjecture.

Here's a challenge that you may wish to try: can you express all the numbers from 1 to 100 using an arithmetic combination of only four 4's? The operations and symbols that are allowed are: the four arithmetic operations (+,x,-,/), concatenation (44 is ok and uses up two 4's), decimal points (using 4.4 is ok), powers (using 4 4 is ok), square roots, factorials (using 4! is ok), and overbars for indicating repeating digits (e.g., writing .4 with an overbar would be a way of expressing 4/9). Ordinary use of parentheses are allowed. No digits other than 4 are allowed. This problem is sometimes called the four fours problem. It was popularized by Martin Gardner, among others. For Example: So... Take out your pen and paper... find all the possibilities from 1 to 100. Write your answers in the comment box.

Dear All Let me share a very interesting question with all of you. If you multiply first 100 natural numbers, how many zeroes will come at the end of this product? Do we really need to multiply all the numbers from 1 to 100 or else you have some logic? Please read below for further details and enjoy solving mathematics! well, class XI and XII students know well about the greatest integer function. Junior class students can also find out a simple logic to solve this problem.